ExplorationsHow e connects repeated growth, infinite sums and a turn around a circle
The Number Behind Continuous Growth
Begin with 1 unit and assign a nominal growth rate of 100% over one unit of time. Adding that growth once gives 2; splitting it into two 50% increases gives 1 × 1.5 × 1.5 = 2.25. Splitting it into n equal increases gives (1 + 1/n)^n, which approaches Euler’s number e, about 2.71828. Follow that limit, then see how powers of e describe growth, decay and rotation.
Interactive laboratory
1 growth interval
(1 + 1/1)^1 ≈ 2
Begin with 1 unit and add 100% of the current amount once. The final amount is 2 units.
Complete calculation transcript
| Step | Calculation |
|---|---|
| (1 + 1/1)^1 ≈ 2 | |
| (1 + 1/2)^2 ≈ 2.25 | |
| (1 + 1/4)^4 ≈ 2.44140625 | |
| (1 + 1/8)^8 ≈ 2.56578451 | |
| (1 + 1/16)^16 ≈ 2.6379285 | |
| (1 + 1/32)^32 ≈ 2.67699013 | |
| (1 + 1/64)^64 ≈ 2.69734495 | |
| (1 + 1/128)^128 ≈ 2.70773902 | |
| (1 + 1/256)^256 ≈ 2.71299162 | |
| (1 + 1/512)^512 ≈ 2.715632 | |
| (1 + 1/1024)^1024 ≈ 2.71695573 |
- dot
- a final amount after n growth intervals
- dashed reference
- a numerical reference, not an error bound
Every dot is the final amount from a fresh experiment starting with 1 unit. Each horizontal step doubles the number of growth intervals; it does not add another period. The dashed line marks e as a numerical reference.
(1 + 1/1)^1 ≈ 2. The numerical reference is 2.71828183.
- Step
- 0 / 10
- Current value
- 2
Try this
Why do two 50% increases produce 2.25 rather than 2?
What is going on
Each explanation begins with a worked example and follows the same operation through intuition, formal statements and proofs. Later sections distinguish what is established from questions that remain open, so you can follow the level of detail useful to you.
- 1add 50% of 1: 1 + 0.51.5This is the first of two equal growth intervals.
- 1.5add 50% of 1.5: 1.5 + 0.752.25The first increase also receives growth during the second interval.
What you are seeing
Each finer split begins again with 1 unit
In the compound-growth view, n tells us how many times growth is added. Each time, the current amount is multiplied by 1 + 1/n. For n = 2, that multiplier is 1.5, applied twice. For n = 4, it is 1.25, applied four times. We hold the nominal total rate at 100%, so increasing n does not mean increasing the rate assigned to each interval.
Run and Step compare n = 1, 2, 4, 8 and so on. A dot represents the final amount from one complete experiment, not the balance halfway through it. The transcript records every calculation, including steps that have not yet been drawn.
Another way to build the same number
A factorial makes successive additions smaller
The exponential function gives meaning to e raised to different powers. In the series view, start with 1, add x, then x²/2!, then x³/3!, and continue. A factorial such as 3! means 3 × 2 × 1 = 6. At x = 1, the first sums are 1, 2, 2.5 and approximately 2.666667. They approach the same e that appeared in compounding.
At x = 2 the sum instead approaches e², about 7.389. At x = −1 it approaches e⁻¹ = 1/e, about 0.367879. Negative powers here describe decay rather than a negative amount. The early partial sums can overshoot or even be negative, especially when x is negative; only the infinite sum is the positive exponential value.
How e meets π on a circle
An imaginary exponent represents a rotation
The imaginary unit i is defined by i² = −1. A complex number a + bi can be drawn at horizontal coordinate a and vertical coordinate b. On Euler’s circle, start at 1, the point (1, 0), and move counterclockwise. A radian measures angle by arc length divided by radius, so a half-turn is π radians and a full turn is 2π radians.
Euler’s formula states that e raised to iθ has coordinates cos θ and sin θ:
At a half-turn, those coordinates are (−1, 0), so e^(iπ) = −1. Adding 1 gives the familiar Euler’s identity, e^(iπ) + 1 = 0. This relates e, π, i, 1 and 0 without claiming that an ordinary positive real power has become negative; the exponent is imaginary.
What about 1/(1 − e)?
A familiar formula can have an unfamiliar condition
The expression 1/(1 − e) is a perfectly well-defined negative number, about −0.581977. It is not the ordinary sum of 1 + e + e² + ⋯. That series keeps adding positive terms which grow larger, so its partial sums cannot approach that negative number.
The relevant formula is 1 + r + r² + ⋯ = 1/(1 − r), and it requires |r| less than 1. Use r = 1/2 to approach 2, or r = 1/e to approach 1/(1 − 1/e), about 1.581977. The comparison view lets you try both convergent ratios and r = e, where the condition fails. Neither series is the factorial-weighted series that defines eˣ.
Why the connections hold
The finite identities explain the limiting operations
For the geometric partial sum Sₘ = 1 + r + ⋯ + rᵐ, multiplying by r and subtracting cancels all the middle terms. Thus (1 − r)Sₘ = 1 − rᵐ⁺¹. If |r| is less than 1, the final power tends to zero, giving the claimed limit. If |r| is at least 1, the terms themselves do not tend to zero, which already rules out ordinary convergence.
For compounding, the binomial theorem gives
Every product lies between zero and one, and for each fixed k it tends to one. The tail is bounded by the corresponding tail of ∑ 1/k!, a convergent series: after the first few terms, each new term is at most half its predecessor. Given any desired error, first choose a small factorial tail, then make n large enough for the remaining finitely many products to be close to one. This proves that the compounding limit is ∑ 1/k! = e.
For a complex exponent iθ, the exponential series is absolutely convergent, so its even and odd powers can be collected separately. Using i² = −1 produces the cosine series in the real part and the sine series in the imaginary part, yielding Euler’s formula.
What the pictures establish
A finite rendering illustrates a theorem rather than proving it
The laboratory uses ordinary floating-point arithmetic. Its dashed references come from the browser’s exponential function, and the circle coordinates come from sine and cosine. These are numerical illustrations, not certified intervals or independently verified digits. The 16-term series can still visibly differ from eˣ, especially near the ends of the allowed range.
The statements above concern limits and exact identities, supported by their arguments and references. Increasing the number of drawn points cannot replace those arguments. A useful next investigation is to compare how quickly the compounding and factorial constructions approach e, then ask what error bound would certify a chosen number of decimal places.
What is actually established
Every statement on this page, with its status, its exact scope, and the date that status was last checked.
As n tends to infinity, (1 + 1/n)^n tends to e.
- Scope
- Positive integer n, with a fresh starting amount of 1 and a nominal total rate of 100%.
- Why
- The binomial expansion is a sum of products bounded by 1/k!. Each fixed product approaches 1/k!, and the tails are controlled by the convergent factorial series. The detailed argument appears below.
- Status checked
- Sources
- DLMF §4.2: Definitions
The infinite series ∑ xᵏ/k! equals eˣ for every real x.
- Scope
- An infinite series; the laboratory displays only 16 terms using floating-point arithmetic.
- Status checked
- Sources
- DLMF §4.2: Definitions
For real θ, e^(iθ) = cos θ + i sin θ, so e^(iπ) + 1 = 0.
- Scope
- Angles in radians and the imaginary unit satisfying i² = −1.
- Status checked
- Sources
- DLMF §4.2: Definitions
The geometric series 1 + r + r² + ⋯ equals 1/(1 − r) exactly when |r| < 1.
- Scope
- Real r and ordinary convergence of partial sums. In particular, r = e is outside this condition.
- Status checked
Sources
Review notes show which bibliographic details Mathomaly has checked and which remain unresolved. Checking a publication record does not independently verify its proof.
- NIST Digital Library of Mathematical Functions, DLMF §4.2: Definitions, National Institute of Standards and Technology. Link
Equations 4.2.11, 4.2.19 and 4.2.24 give the constant e, the exponential power series and its real and imaginary parts.
Bibliographic record checked. This is not an independent verification of the proof.
Bibliographic review:
AI-assisted bibliographic audit. Evidence type: source text.
Read the institutional reference, its exponential-series definition and its real/imaginary decomposition. This records source identity, not an independent proof audit.
- Gilbert Strang, Edwin Herman, Calculus Volume 2, §5.2: Infinite Series, OpenStax, Rice University. Link
The geometric-series calculation states its convergence condition and derives the finite partial-sum identity.
Bibliographic record checked. This is not an independent verification of the proof.
Bibliographic review:
AI-assisted bibliographic audit. Evidence type: source text.
Read the publisher-hosted geometric-series section and its condition |r| < 1. This is bibliographic verification, not an independent proof audit.
Related by mechanism
Connected by how they work, not by sharing a topic label.